Campuses:
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This section covers how to solve the Schroedinger Eqn by separating x and t using the technique called separation of variables. This is possible because the potential energy V(x) is usually a function of only x, and not t.
Using the Schroedinger Eqn, boundary condition(s) and normalization condition, we will find still a number of (sometime infinite) solutions each of which is expressed as a product of a function of x and a function of t. The latter takes a form of <math>e^{-i\omega t}</math>, where <math>\omega = \frac{E}{\strike h}</math>.
The infinite square well is the special case of a potential well where the potential inside the well is 0 and the potential outside is infinite. There is zero probability for a particle to be outside the well. Solutions for ψ:
Also, ψ will not be smooth at the edges of the well.
Steady State Solutions: ψn=sqrt(2/L)*sin(nπx/L) (where L is the width of the well, n is an integer)
<math>\psi_n(x)=\sqrt{\frac{2}{L}}\sin{\frac{n\pi x}{L}}</math>
The General Solution: Ψ(x,t)=∑c(n)*sqrt(2/L)*sin(nπx/L)*e^[(-i*n^2*π^2*hbar*t/(2*m*L^2)]
The c(n)'s are just coefficients of the ψn's as they are sumed, so that some of them are weighted more than others. In class, we discussed how |c(n)|^2 can be thought of as a “probability” that the particle is in state n. Really, the wavefunction describing the particle is composed of a little bit of many states, and the coefficients (the c(n)'s) dictate how much state each contributes to the general solution of the particle.
The ENERGY of a state is contained in the time-dependent piece's exponent: E(n)=(hbar^2*k(n))/(2*m) =(n^2*π^2*hbar^2)/(2*m*L)