Campuses:
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classes:2009:fall:phys4101.001:lec_notes_1012 [2009/10/14 08:21] – x500_spil0049 | classes:2009:fall:phys4101.001:lec_notes_1012 [2009/10/14 08:35] (current) – x500_spil0049 | ||
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Next we need to know the energy of the system under consideration. Is E < 0 or E > 0.\\ | Next we need to know the energy of the system under consideration. Is E < 0 or E > 0.\\ | ||
With this information one can now divide the problem into regions. That is, both regions outside the potential well and the region in between the potential " | With this information one can now divide the problem into regions. That is, both regions outside the potential well and the region in between the potential " | ||
+ | 2nd\\ | ||
+ | We impose boundary conditions.\\ | ||
+ | ψ and dψ must be continuous at the boundarys\\ | ||
+ | Upon analysis of the potential being an even function we can assume that the solutions are either even or odd. This is advantages b/c we only need to impose boundary conditions | ||
The first point to consider is that an odd solution will be antisymmetric across the origin. This is what we focused on today. | The first point to consider is that an odd solution will be antisymmetric across the origin. This is what we focused on today. | ||