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classes:2009:fall:phys4101.001:lec_notes_1012

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classes:2009:fall:phys4101.001:lec_notes_1012 [2009/10/14 08:32] x500_spil0049classes:2009:fall:phys4101.001:lec_notes_1012 [2009/10/14 08:35] (current) x500_spil0049
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 We impose boundary conditions.\\  We impose boundary conditions.\\ 
 ψ and dψ must be continuous at the boundarys\\  ψ and dψ must be continuous at the boundarys\\ 
- +Upon analysis of the potential being an even function we can assume that the solutions are either even or odd. This is advantages b/c we only need to impose boundary conditions  on one side of the well.
 The first point to consider is that an odd solution will be antisymmetric across the origin. This is what we focused on today. The first point to consider is that an odd solution will be antisymmetric across the origin. This is what we focused on today.
  
classes/2009/fall/phys4101.001/lec_notes_1012.1255527151.txt.gz · Last modified: 2009/10/14 08:32 (external edit)