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classes:2009:fall:phys4101.001:lec_notes_1016 [2009/10/17 23:12] – x500_nikif002 | classes:2009:fall:phys4101.001:lec_notes_1016 [2009/10/17 23:50] (current) – x500_nikif002 | ||
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< | < | ||
where < | where < | ||
- | *//the reason we can do this is because all stationary states are orthonormal// | + | *//the reason we can do this is because all stationary states are orthonormal. The stationary states in function space are like the basis vectors in //< |
*the above vector can have finite or infinite number of components depending on how many stationary states there are. | *the above vector can have finite or infinite number of components depending on how many stationary states there are. | ||
*in the language of vectors, operators are transformations and are featured by Matrices. (I think one point of the lecture was the following: by operation on a function you get another function analogous to for example when you apply addition rules on a vector you get another vector which belongs to the original vector space) | *in the language of vectors, operators are transformations and are featured by Matrices. (I think one point of the lecture was the following: by operation on a function you get another function analogous to for example when you apply addition rules on a vector you get another vector which belongs to the original vector space) | ||
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< | < | ||
*determinate state is a state with no uncertainty and each measurement of some quantity Q gives back the same result q. //In other words, the standard deviation of the observable is 0.// | *determinate state is a state with no uncertainty and each measurement of some quantity Q gives back the same result q. //In other words, the standard deviation of the observable is 0.// | ||
- | *//This is something that confused me. Which operators can we define an eigenvalue for? All linear operators? All Hermitian operators? Certainly we can define some non-linear operators that don't have eigenvalues (such as the squaring operator). Looking at the book, it explains it. Determinate states for an operator Q are states that are eigenfunctions of Q. So //< | + | *//This is something that confused me. Which operators can we define an eigenvalue for? All linear operators? All Hermitian operators? Certainly we can define some non-linear operators that don't have eigenvalues (such as the squaring operator). Looking at the book, it explains it. Determinate states for an operator Q are states that are eigenfunctions of Q. So //< |
*//Another new piece of notation: //< | *//Another new piece of notation: //< | ||