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classes:2009:fall:phys4101.001:q_a_1104 [2009/11/04 10:25] – x500_maxwe120 | classes:2009:fall:phys4101.001:q_a_1104 [2009/12/19 16:56] (current) – x500_sohnx020 | ||
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- | ===== Nov 04 (Wed) ===== | + | ===== Nov 04 (Wed) Laplacian in spherical coordinate, Legendre |
**Return to Q&A main page: [[Q_A]]**\\ | **Return to Q&A main page: [[Q_A]]**\\ | ||
**Q&A for the previous lecture: [[Q_A_1102]]**\\ | **Q&A for the previous lecture: [[Q_A_1102]]**\\ | ||
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**Main class wiki page: ** [[home]] | **Main class wiki page: ** [[home]] | ||
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====Ekrpat 1144 12:50pm==== | ====Ekrpat 1144 12:50pm==== | ||
A simple question about tuesday' | A simple question about tuesday' | ||
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+ | ====Captain America 11/4 10:37==== | ||
+ | When dealing with the Hydrogen atom, we assume that the proton is a potential well for the electron. | ||
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+ | I'm also confused as to why we can call the proton a well, instead of calling it a wave function well, since in quantum mechanics all particles can be described as wave functions. | ||
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+ | ===prest121 11/4 12:30 === | ||
+ | When dealing with the hydrogen (or single-electron) atom, we make the assumption of a stationary nucleus. | ||
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+ | I think this is what leads to us treating the proton as a 1/r potential well and the electron as a wave function/ | ||
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+ | ===Pluto 4ever 11/5 11:11am=== | ||
+ | I also agree with this. We generally want to focus on the electron as opposed to the proton which we are assuming is stationary. That way in this ideal situation it becomes less complex to calculated the properties of the electron to some degree, such as such as probability of position and momentum, as well as energy and spin states. | ||
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+ | ===Captain America 11/6 10:13am=== | ||
+ | But then why don't we treat the potential as a wavefunction? | ||
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+ | ===David Hilbert' | ||
+ | I tend to think that the effective wavefunction of a proton is very small relative to the potential it produces - for instance, whatever the effective " | ||
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+ | ====Dark Helmet 11/05==== | ||
+ | Although i understand how to get them, what exactly is the physical interpretation of eigenstates and eigenvalues? | ||
+ | === Blackbox === | ||
+ | In quantum mechanics, operators correspond to observable variables, eigenvectors are also called eigenstates, | ||