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classes:2009:fall:phys4101.001:q_a_1111 [2009/11/10 20:14] gebrehiwetclasses:2009:fall:phys4101.001:q_a_1111 [2009/11/16 22:20] (current) yk
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-===== Nov 11 (Wed)  =====+===== Nov 11 (Wed) Radial Wave Function (finite well, hydrogen) =====
 **Return to Q&A main page: [[Q_A]]**\\ **Return to Q&A main page: [[Q_A]]**\\
 **Q&A for the previous lecture: [[Q_A_1109]]**\\ **Q&A for the previous lecture: [[Q_A_1109]]**\\
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 Thanks! Thanks!
-   
  
 +=== liux0756 11/11/2009 4:00pm ===
 +Yes, simultaneous eigenstates are important. Generally speaking if two operators do not have simultaneous eigenstates, then they can't be measured at the same time. For example, x and p do not have simultaneous eigenstates, so we can't get the exact value of x and p at the same time: <math>\delta x \delta p \ge \hbar/2</math> But angular momentum <math>l^2</math> and <math>l_z</math> have common eigenstates and in those states both of them can have exact measurement.
 +====Dagny====
 +Basic question: How do we go (what's the process) from dxdydz to <math>r^2sin\theta</math><math>dr</math><math>d\theta</math><math>d\phi</math>
 +===Blackbox 11/12/2009 12:15pm===
 +The process is simple, dxdydz=dv for the cartesian coordinate system. In similar way, dv for the spherical coordinate system is <math>dr*rd\theta*rsin\theta d\phi</math>. It may be easily understood if you look at the sherical coordinate system plot from any EM refernece book.
  
 +===Daniel Faraday 11/12 10:30pm===
 +Wait a second: the sin term isn't squared in dV, is it? I thought dV was just 
 +<math>r^2sin\theta dr d\theta d\phi</math>  ?? 
  
 +===Dagny===
 +Correct!
 +
 +
 +
 +====Blackbox 11/12/2009 11:50am====
 +I just forgot,, Could anyone tell me about the unit of <math> k=\frac{sqrt{2mE}}{\hbar} </math>? Thanks,
 +
 +===liux0756===
 +The unit of k is [length]^-1. Because momentum <math>p=\hbar k</math>, angular momentum <math> L= n \hbar = momentum*length </math>, so k is [length]^-1.
 +
 +
 +====Dagny====
 +What is the very detailed process for the transformation of the gradient operator from cartesian to spherical coordinates? Just one operator term is fine, like del/delx. (Because I'm just interested in the process and also how we come about this process.) I've found a couple of website examples on how to do it, but nothing that provides a clear explanation. 
  
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 **Q&A for the previous lecture: [[Q_A_1109]]**\\ **Q&A for the previous lecture: [[Q_A_1109]]**\\
 **Q&A for the next lecture: [[Q_A_1113]]** **Q&A for the next lecture: [[Q_A_1113]]**
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classes/2009/fall/phys4101.001/q_a_1111.1257905673.txt.gz · Last modified: 2009/11/10 20:14 by gebrehiwet