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--- classes:2009:fall:phys4101.001:q_a_1118 [2009/11/18 23:37] – gebrehiwet
+++ classes:2009:fall:phys4101.001:q_a_1118 [2009/11/30 09:00] (current) – x500_bast0052
@@ Line 38: / Line 38: @@
 ===Esquire (Age of No Ideas)===
 I have no idea what an eigenspinor physically represents.
+==Devlin==
+Neither do I.
 ===Green Suit 11/17===
 This is what I found on Wikipedia:
@@ Line 65: / Line 69: @@
 ===David Hilbert's Hat 11/18 2pm===
 Do you mean ψ or χ?
+===David Hilbert's Hat 11/18 2pm===
+As far as I can tell, a and b are always given or just some constants, so you can use [4.139] as well as the corresponding eigenvalue for whatever operator you're looking at. It is done in example 4.2 in the book for <math> S_{z} </math> and <math> S_{x} </math>.
 ====Schrodinger's Dog 11/18====
 χ
@@ Line 94: / Line 102: @@
 ====Pluto 4ever 11/18 5:30PM====
 Does the value of the quantum number s depend on m, or is it completely independent of the other terms and deals with purely spin alone?
+===The Doctor 11/19 12:02AM===
+Equation 4.137 should solve the question.
+I looks like s is a fixed value for a particular particle while m can change depending on the state of that particle.  From what I can tell m is actually dependent on s which is independent of the other numbers.  It just has to do with the properties of the particle.
+==David Hilbert's hat 11/20 11am==
+Usually I think of s as being like a constant for each particle; all electrons have spins of 1/2, photons have spin of 1, and so on for every particle. Then when you measure it, spin can be up or down, so the <math> m_{s}</math> value can be plus or minus s, or any integer value in between (like <math> m_{l} </math> is for l). So the s value itself tells you something like the magnitude and the m value tells you which direction it's pointing in.
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